## X(3041) (COMPLEMENT OF X(1362))

 Interactive Applet

You can move the points A, B and C (click on the point and drag it).
Press the keys “+” and “−” to zoom in or zoom out the visualization window and use the arrow keys to translate it.

You can also construct all centers related with this one (as described in ETC) using the “Run Macro Tool”. To do this, click on the icon , select the center name from the list and, then, click on the vertices A, B and C successively.

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This applet was built with the free and multiplatform dynamic geometry software C.a.R..

 Information from Kimberling's Encyclopedia of Triangle Centers

Trilinears            f(a,b,c) : f(b,c,a) : f(c,a,b), where f(a,b,c) = bc[b2(a2 - ab - bc + c2)2/(a - b + c) + c2(a2 - ac - bc + b2)2/(a + b - c)]
Barycentrics    af(a,b,c) : bf(b,c,a) : cf(c,a,b)

X(3041) lies on the Spieker circle and these lines:
2,1362    8,3022    9,1282    10,2808    101,958    103,1376    118,124    150,2551    152,2550    928,3040    960,2809    2801,3035

X(3041) = midpoint of X(8) and X(3022)
X(3041) = complement of X(1362)

This is a joint work of
Humberto José Bortolossi, Lis Ingrid Roque Lopes Custódio and Suely Machado Meireles Dias.