You can move the points A, B and C (click on the point and drag it).
Press the keys “+” and “−” to zoom in or zoom out the visualization window and use the arrow keys to translate it.
You can also construct all centers related with this one (as described in ETC) using the “Run Macro Tool”. To do this, click on the icon , select the center name from the list and, then, click on the vertices A, B and C successively.
|Information from Kimberling's Encyclopedia of Triangle Centers|
Trilinears f(a,b,c) : f(b,c,a) : f(c,a,b), where f(a,b,c) = bc[-1/a2 + 1/b2 + 1/c2 + 1/(bc) + 1/(ca) + 1/(ab)]
Barycentrics g(a,b,c) : g(b,c,a) : g(c,a,b), where g(a,b,c) = -1/a2 + 1/b2 + 1/c2 + 1/(bc) + 1/(ca) + 1/(ab)
Continuing from the description of X(1654), let h(B,A) be the distance from the point Ba to the line CA, and define five other distances cyclically. If P = X(1655), then
h(B,A) + h(C,A) = h(C,B) + h(A,B) = h(A,C) + h(B,C)
(Antreas Hatzipolakis, Anopolis #20, 1/20/02)
X(1655) lies on these lines: 2,39 8,192 21,385 193,452 350,1107 668,1500
X(1655) = anticomplement of X(274)
X(1655) = X(I)-Ceva conjugate of X(J) for these (I,J): (37,2), (1909,8)