## X(1084) (CROSSPOINT OX X(2) AND X(512))

 Interactive Applet

You can move the points A, B and C (click on the point and drag it).
Press the keys “+” and “−” to zoom in or zoom out the visualization window and use the arrow keys to translate it.

You can also construct all centers related with this one (as described in ETC) using the “Run Macro Tool”. To do this, click on the icon , select the center name from the list and, then, click on the vertices A, B and C successively.

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Download all construction files and macros: tc.zip (10.1 Mb).
This applet was built with the free and multiplatform dynamic geometry software C.a.R..

 Information from Kimberling's Encyclopedia of Triangle Centers

Trilinears            a3(b2 - c2)2 : b3(c2 - a2)2 : c3(a2 - b2)2
Barycentrics    a4(b2 - c2)2 : b4(c2 - a2)2 : c4(a2 - b2)2

Let f(a,b,c) = a3(b2 - c2)2. Then the line
f(a,b,c)x + f(b,c,a)y + f(c,a,b)z = 0 is tangent to the circumcircle at X(99).

X(1084) lies on these lines: 2,670    6,694    39,597    115,804    351,865

X(1084) = midpoint of X(6) and X(694)
X(1084) = complement of X(670)
X(1084) = crosspoint of X(2) and X(512)
X(1084) = crosssum of X(I) and X(J) for these (I,J): (6,99), (76,670), (799,873)
X(1084) = crossdifference of any two points on line X(99)X(670)

This is a joint work of
Humberto José Bortolossi, Lis Ingrid Roque Lopes Custódio and Suely Machado Meireles Dias.

If you have questions or suggestions, please, contact us using the e-mail presented here.

Departamento de Matemática Aplicada -- Instituto de Matemática -- Universidade Federal Fluminense